RE: [xsl] Can I take only parts from node value?

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RE: [xsl] Can I take only parts from node value?

Subject: RE: [xsl] Can I take only parts from node value?
From: "Michael Kay" <michael.h.kay@xxxxxxxxxxxx>
Date: Tue, 19 Feb 2002 17:05:31 -0000

> If I have XML-tag like this:
> 
> <today date="200202190800" />
> 
> and I want output:
> 
> Time is 08:00
> Date is 19.02 
> Year is 2002
> 
> How can I do this with XSL/T? 

With the substring() function.

Michael Kay
Software AG
home: Michael.H.Kay@xxxxxxxxxxxx
work: Michael.Kay@xxxxxxxxxxxxxx 

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RE: [xsl] regd: XSLT in SAXON, (continued) Michael Kay - Tue, 19 Feb 2002 14:25:00 -0000 jp - Tue, 19 Feb 2002 16:58:28 +0100 Robert Koberg - Tue, 19 Feb 2002 08:07:32 -0800 Oleg Tkachenko - Tue, 19 Feb 2002 18:21:41 +0200 Michael Kay - Tue, 19 Feb 2002 17:05:31 -0000 <= jp - Tue, 19 Feb 2002 18:27:56 +0100

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