RE: [xsl] embedded <xsl-for-each>

["Andrew Welch" <awelch@xxxxxxxxxxxxxxx>]

Hi,

Which value are you after?  As you use <xsl:for-each> to step through each
/FLOW-MENU-GRP/FAMILY, and then a another <xsl:for-each> to step though each
/FLOW-MENY-GRP/SERVICE, its not clear why you could not use position() on
the 'service' elements to give you the same id number as that of the
'family' elements.  If the number of each of type of element differs, what
id number would you want then?

If you post some sample data and the kind of result you are looking for,
then your requirements will become clearer.

cheers

andrew

===


-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Sébastien
Tisserant
Sent: Thursday, February 21, 2002 1:24 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] embedded <xsl-for-each>


hello

i have this template:

<xsl:template match="FLOW-MENU-GRP">    <xsl:for-each
select="/FLOW-MENU-GRP/FAMILY">      <DIV>        <xsl:attribute
name="ID"><xsl:value-of select="position()"/></xsl:attribute>
<xsl:value-of select="text()"/>      </DIV>            <xsl:for-each
select="/FLOW-MENU-GRP/SERVICE">              <DIV>
<xsl:attribute name="ID">here i'd like to get the value of position() given
above in line 4</xsl:attribute>               <xsl:value-of
select="text()"/>
             </DIV>           </xsl:for-each>
</xsl:for-each></xsl:template>

is this possible using and ancestor path? how should i write it?

is this possible using <xsl:variable>? how should i use it?

thanks

sébastien


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