Subject: [xsl] Stuck with Jeni's Logic...Help me out..!! From: "Sachidanandam E K" <sachidanandam.kumaraswamy@xxxxxxxxxxxxxx> Date: Wed, 4 Apr 2001 15:13:18 +0530 |
Hi Jeni and Hi all.. My need is to get a different of A (xml file) and B (xml File) and then get C (as xml file). I used the logic explained in the below link as jeni explained it. http://sources.redhat.com/ml/xsl-list/2000-07/msg00320.html Still not able to get a clear picture upon it. When telling about XML files i can post it when anone wish to see it . Let me have a reply upon this. Sample XML is below: A.xml. ------- <RecipeVersions> <RecipeVersion> <VersionID>{007A6506-B4E1-4F2C-B4CD-A725B41DDA33}</VersionID> <BodySize>100</BodySize> <Identifier>Anoop>/RBClass1/Test111</Identifier> <Version>1</Version> </RecipeVersion> <RecipeVersion> <VersionID>{010EA2DE-1063-47B8-82FF-4D15EA0BCA2A}</VersionID> <BodySize>100</BodySize><Identifier>Anoop>/RBClass1/Test198</Identifier> <Version>1</Version></RecipeVersion> <RecipeVersion><VersionID>{1ED0B241-862C-4803-98BF-8E1385A38AAE}</VersionID> <BodySize>100</BodySize><Identifier>Anoop>/RBClass1/Test134</Identifier>< Version>1</Version></RecipeVersion> </RecipeVersions> In the similar way b.xml will be there. Based on VersionID I need to compare A wish B and put into C elements of A which is not found in B.xml. Hoping to get a reply. Thanks in advance Sachi.. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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