Subject: Re: [xsl] Ignoring default attributes during XSL transform From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> Date: Thu, 18 Apr 2002 17:03:07 -0400 |
Cheers, Wendell
Correct, that I understand. But I am wondering if there is a way to compare the value in the tree with an attribute's default value defined in the DTD. Something like this:
<xsl:apply-templates select="*@[. != '{attribute's default val}']"/>
I would like to only output the attributes which are not the default value to make the outputted xml more readable. I have about 30 attributes but most of then are just set to their default values.
Thank You, Manny
At 12:23 PM 4/18/2002 +0200, Joerg Heinicke wrote:As far as I know, the default value (from DTD) of attributes are added by the parser (please correct me if I'm wrong). So when the stylesheet gets the document, every attribute is in the XML tree. But the stylesheet knows nothing about whether it's a default value - the attribute is in the tree, not more, not less.
Regards,
Joerg
Manny Parasirakis wrote:My follow on question is whether or not there is a way to compare an attribute value to its default value defined in the DTD?
At 10:02 PM 4/17/2002 +0200, Joerg Heinicke wrote:
<xsl:apply-templates select="* | @*[. != '']">
Regards,
Joerg
Manny Parasirakis wrote:
I am trying to figure out how I can ignore outputting attributes whose values are not set (=""). I am fairly new at this but cannot figure it out. I need to do this for all XML tags. Here is my XSL:
<xsl:template match="*|@*">
<xsl:copy>
<xsl:apply-templates select="*|@*"/>
</xsl:copy>
</xsl:template>
I've tried a bunch of things but cannot figure this out.
--
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