Subject: Re: [xsl] [java] transforming a file to itself - buffered? From: "J.Pietschmann" <j3322ptm@xxxxxxxx> Date: Tue, 04 Jun 2002 22:59:01 +0200 |
What is the best way to handle transforming a file to itself?
Currently I do: File source = new File(servlet_context.getRealPath(_xml)); transformer.transform(new StreamSource(source), new StreamResult(source));
Opening a file both for reading and writing at the same time is always risky. Either write to a buffer, and write the buffer to disk after the transformation has finished, or write to a temporary file and rename to the original file afterwards. Something like; ByteArrayOutputStream baos=new B...; File source = new File(servlet_context.getRealPath(_xml)); transformer.transform(new StreamSource(source), new StreamResult(baos)); byte buf[]=baos.toByteArray(); new FileOutputStream(source).write(buf);
BTW doing this in a servlet context appears to be rather strange...
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