Subject: [xsl] node() as pattern From: DPawson@xxxxxxxxxxx Date: Wed, 12 Jun 2002 14:37:25 +0100 |
I'm having a problem understanding the use of node() in a pattern. given a simple file (pretend no whitespace) <doc> <nd1> ..</nd1> <nd2>..</nd2> <nd3/> </nd1> </doc> I believe I can get to any node using a node based pattern, e.g. <xsl:template match='/node()[1]/node()[2]'> should match on nd3 but my theory isn't working out. Anyone got a nice clear description of what's happening with such as match='/node()[2]/node()[8]/node()[2]/node()[8]/node()[7]' please? Mikes book, 432 tells me node() == ./child::node() So with a stylesheet full of 'only' matches of this form, all root relative, none of the templates are instantiated. regards DaveP ************snip here************** - NOTICE: The information contained in this email and any attachments is confidential and may be legally privileged. If you are not the intended recipient you are hereby notified that you must not use, disclose, distribute, copy, print or rely on this email's content. If you are not the intended recipient, please notify the sender immediately and then delete the email and any attachments from your system. RNIB has made strenuous efforts to ensure that emails and any attachments generated by its staff are free from viruses. However, it cannot accept any responsibility for any viruses which are transmitted. We therefore recommend you scan all attachments. Please note that the statements and views expressed in this email and any attachments are those of the author and do not necessarily represent those of RNIB. RNIB Registered Charity Number: 226227 Website: http://www.rnib.org.uk 14th June 2002 is RNIB Look Loud Day - visit http://www.lookloud.org.uk to find out all about it. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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