Subject: RE: [xsl]: Finding the deepest node(s) From: "Michael Kay" <michael.h.kay@xxxxxxxxxxxx> Date: Tue, 18 Jun 2002 14:11:00 +0100 |
> -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of > TSchutzerWeissmann@xxxxxxxxxxxxxxxx > Sent: 18 June 2002 11:56 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl]: Finding the deepest node(s) > > > Is there an XPath to find the deepest node(s) in some xml, ie > the node(s) with more parents than any others? Not in a single XPath expression, because existential quantification is only available when comparing nodes according to their string-value. Try the higher-order Saxon extension functions: saxon:highest(//node(), saxon:expr('count(ancestor::*)') or check Dimitre's dynamic templates. Michael Kay Software AG home: Michael.H.Kay@xxxxxxxxxxxx work: Michael.Kay@xxxxxxxxxxxxxx XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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