Subject: Re: [xsl] basic xpath question From: "Vasu Chakkera" <vasucv@xxxxxxxxxxx> Date: Thu, 20 Jun 2002 12:25:13 +0000 |
Cheers Vasu
From: "Hanlan, Dominic - Senior Developer" <dhanlan@xxxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: "'XSL-List@xxxxxxxxxxxxxxxxxxxxxx'" <XSL-List@xxxxxxxxxxxxxxxxxxxxxx> Subject: [xsl] basic xpath question Date: Thu, 20 Jun 2002 10:11:25 +0100
Hi,
I have an xml document to be styled, if I have a construct such as
<section id="para">this is text <section id="url" url="http://xx.yy.zz">which is to be a link</section></section>
How do I, in xslt, recognise the "url" tag within the "para" tag, such that I could ouput someting like
<p>this is test <a href="http://xx.yy.zz">which is to be a link</a></p>
Regards
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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