Subject: RE: [xsl] accessing URL parameters from XSL From: Paul Zwarts <Paul.Zwarts@xxxxxxxxxxx> Date: Mon, 4 Nov 2002 13:13:03 +0100 |
Victor, If you are using ASP, you can capture the request variable and pass it into the ms-xml parser in such way: Set XMLSource = Server.CreateObject("MSXML2.DOMDocument.4.0") XMLSource.Load (lStrRootDir & "\data\directory.xml") Dim XSLTSource Set XSLTSource = Server.CreateObject("MSXML2.FreeThreadedDOMDocument.4.0") XSLTSource.Load (lStrRootDir & "\directory.xsl") Dim Transform Set Transform = Server.CreateObject("MSXML2.XslTemplate.4.0") Set Transform.Stylesheet = XSLTSource Dim XMLProcessor Set XMLProcessor = Transform.CreateProcessor XMLProcessor.Input = XMLSource >> XMLProcessor.AddParameter "CurrentUser", requet("<YourVarNameHere>") Call XMLProcessor.Transform lObjStrOutput = XMLProcessor.Output Paz -----Original Message----- From: Viktor [mailto:viktoras@xxxxxx] Sent: maandag 4 november 2002 13:36 To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] accessing URL parameters from XSL Hello all, I'm having problem with accessing URL parameters from XSL. How can I solve this problem? I'm using server-side Microsoft MSXML parser. Viktor. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
RE : [xsl] process the result tree , Nicolas Mazziotta | Thread | [xsl] accessing URL parameters from, Viktor |
Re: [xsl] accessing URL parameters , Oleg Tkachenko | Date | [xsl] accessing URL parameters from, Viktor |
Month |