Subject: Re: [xsl] XPath expression for finding out the depth of a given node? From: Peter Davis <pdavis152@xxxxxxxxx> Date: Sun, 17 Nov 2002 12:25:07 -0800 |
-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 On Sunday 17 November 2002 12:10, Peter Davis wrote: > count(ancestor-or-self::*) On second thought, you would need to change that to count(ancestor-or-self::node()), to be consistant with text() and other nodes. Or, you could just do count(ancestor::*)+1. Hope you get the idea. - -- Peter Davis -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.0.7 (GNU/Linux) iD8DBQE91/sjhDAgUT1yirARAnXbAJ9Zm0xchJCMmJfZ/c3k2IjRhIGMjgCfVXBf HhmhMpmq/EF16s0ZgvR1euU= =fBCl -----END PGP SIGNATURE----- XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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