Re: [xsl] XPATH or 2 templates ?

[David Carlisle <davidc@xxxxxxxxx>]

> <?xml-stylesheet type="text/xsl" href="E:\Zvxml\XtraTest\Test.xsl"?>

If your processor finds the stylesheet from that href it is being
unnecessarily kind to you. It should be a URI, the above refers to
some unregistered uri scheme E:
it should be
file:///E:/Zvxml/XtraTest/Test.xsl"


> Why can I not have template match on <Concat> and <Concat/*> within the same
> stylesheet ? 

You can, why do you think you can not?


> <xsl:text>&#13;</xsl:text> 	

You should use 
<xsl:text>&#10;</xsl:text> 
to get a newline, using 10 will give you an XML normalised line end
which will most likely be output by as a line end suitable for your
machine type. If you generate a 13 then the results are less
predictable, most likely you will just get a single character 13, which
may or may not be the right line end marker for your machine type.

I _think_ you want one line for each child of <Concat> so your second
part should look like

<xsl:for-each select="*">
<xsl:text>&#10;</xsl:text>
<!--
 and on this line you want all the descendent text separated by ;
-->
<xsl:for-each select=".//*[not(*)]">
<xsl:value-of select="."/>
<xsl:if test="position()!=last()">;</xsl:if>
</xsl:for-each> 
</xsl:for-each> 


David


_____________________________________________________________________
This message has been checked for all known viruses by Star Internet
delivered through the MessageLabs Virus Scanning Service. For further
information visit http://www.star.net.uk/stats.asp or alternatively call
Star Internet for details on the Virus Scanning Service.

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list