Subject: Re: [xsl] Carriage Return & # 13 ; From: Gunther Schadow <gunther@xxxxxxxxxxxxxxxxxxxxxx> Date: Tue, 03 Dec 2002 16:57:45 -0500 |
You are looking for a line break, which may not be the same as carriage return. I am not sure what the rules really are on line break normalization or if any of that is done in text nodes. I believe not. So, you need to seach for and or any combination thereof.
<Text>This is a carriage return</Text>
2.a) This is the template I wrote:
-------------------------
<xsl:template name="Text" mode="Text"> <xsl:param name="Text"/> <xsl:variable name="UC13"> </xsl:variable> <xsl:choose>
<xsl:when test="contains($Text,$UC13)">
<xsl:call-template name="Text">
<xsl:with-param name="Text" select="concat(substring-before($Text,'$UC13'),' UC13 ',substring-after($Text,'$UC13'))"/>
</xsl:call-template>
</xsl:when>
</xsl:choose>
why do you use mode and param here? They do not pertain to the problem you're describing. Suggest:
I can see that this template doesn't work, but stack overflow? You are doing other screwy things perhaps :-)
Your XSLT style is too procedural. Try avoiding use of xsl:choose and xsl:call-template. You seem to be breaking the text node only in order to glue it back together. Why? What is it you want to accomplish?
You definitely have all the original line break characters inside text node, the preserve-space etc. has nothing to do with what's going on *inside* a text node. You definitely will find the line break characters in the test node with contains and substring-before etc.
regards, -Gunther
-- Gunther Schadow, M.D., Ph.D. gschadow@xxxxxxxxxxxxxxx Medical Information Scientist Regenstrief Institute for Health Care Adjunct Assistant Professor Indiana University School of Medicine tel:1(317)630-7960 http://aurora.regenstrief.org
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