Subject: RE: [xsl] xsl filter problem From: "Yuval" <yuvalkro@xxxxxxxxxxxx> Date: Thu, 26 Dec 2002 12:10:01 +0200 |
Hi again, My xml looks like this : <customers> <customer> <city>a</city> <name>Jhon<name> </customer> <customer> <city>b</city> <name>Don<name> </customer> <customer> <city>c</city> <name>Ron<name> </customer> </customers> The data is to presented in a table and I want to filter it according to the "city" - meaning I have 4 options : 1.a 2.b 3.c 4.all the cities = no filter Im using a html select box to let the user choose which city to filter and the first option is "all cities".for this parameter I give the value *. The xsl looks like this : <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml" encoding="windows-1255" /> <xsl:param name="city" /> <xsl:template match="/"> <customers> <xsl:for-each select="customers/customer[city=$city]"> <customer> <xsl:for-each select="*"> <xsl:element name='{name()}'> <xsl:value-of select="." /> </xsl:element> </xsl:for-each> </customer> </xsl:for-each> </customers> </xsl:template> </xsl:stylesheet> When choosing "all cities" - the result is an empty table instead of the list of all cities with the customers names. I tried to giva the param "city" a diect value of "*" or " '*' " and it still didn't work. How can I pass a value to this param which will act like : <xsl:for-each select="customers/customer[city=*]"> ?? Thanks in advance XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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