[xsl] omitting empty elements when copying

Subject: [xsl] omitting empty elements when copying
From: "Hesselberth, Jan" <Jan.Hesselberth@xxxxxxxxxxxxxxxxxx>
Date: Wed, 5 Feb 2003 11:56:05 -0000
I know this must be in the archives somewhere but I can't find it.
I have the following xml

	<CUSTOMERDATA>
		<Applicnt>
			<AT_Client_No>1</AT_Client_No>
			<AT_Mf_Client_No/>
			<AT_New_Mf_Cust_No/>
			<AT_Surname>Smith</AT_Surname>
			<AT_Initials>BG</AT_Initials>
			<AT_Forename_1>Bob</AT_Forename_1>
			<AT_Forename_2></AT_Forename_2>
			<AT_Display/>
			<AT_Title_Seq>1</AT_Title_Seq>
			<AT_Date_Of_Birth>12/03/1963
00:00:01</AT_Date_Of_Birth>
			<AT_Age_Now/>
		</Applicnt>
	<CUSTOMERDATA>

I want to copy only the elements with content to get

	<CUSTOMERDATA>
		<Applicnt>
			<AT_Client_No>1</AT_Client_No>
			<AT_Surname>Smith</AT_Surname>
			<AT_Initials>BG</AT_Initials>
			<AT_Forename_1>Bob</AT_Forename_1>
			<AT_Forename_2></AT_Forename_2>
			<AT_Title_Seq>1</AT_Title_Seq>
			<AT_Date_Of_Birth>12/03/1963
00:00:01</AT_Date_Of_Birth>
		</Applicnt>
	<CUSTOMERDATA>

Is there an efficient way of doing this or do I have to test for there being
content in each element and then use xsl:copy?
I had hoped there may be a way to do it with xsl:copy.

Regards
	Jan




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