[xsl] displaying position of nodes

Subject: [xsl] displaying position of nodes
From: "Mac Martine" <email@xxxxxxxxxxxxxxxx>
Date: Thu, 20 Feb 2003 13:06:37 -0800
Argh.
I'm trying to loop through all the nodes and display the position of the
node next to the value of the node. The values display, but only one of
the positions displays. Why is that??? The same happens if I try to
display local-name().
Thanks-
 Mac

XSL
===========================
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:template match="/">
	<body>
		<xsl:apply-templates  />
	</body>
</xsl:template>

<xsl:template match="*">
	<xsl:value-of select="."/>
	<xsl:value-of select="position()"/>
</xsl:template>

</xsl:stylesheet>

XML
============================
<root>
<desktop>
<window>main</window>
<window>sub</window>
<pane>
<button>one</button>
<button>two</button>
</pane>
</desktop>
</root>

RESULT
Displays: 
main sub one two 1
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