Subject: [xsl] Re: Creating a XSL to return the input From: "Dimitre Novatchev" <dnovatchev@xxxxxxxxx> Date: Tue, 4 Mar 2003 21:25:57 +0100 |
"John Chen" <jchen@xxxxxxxxxxxx> wrote in message news:5.0.2.1.0.20030304115132.00b604e0@xxxxxxxxxxxxxxxxxxxx > I would like to create an XSL that takes an XML file and returns it as its > output. Is that easy to do? Yes, use: <xsl:copy-of select="/"/> A lot more useful (because it can be overridden) is the following template, known as the "identity transformation": http://www.w3.org/TR/xslt#copying <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> ===== Cheers, Dimitre Novatchev. http://fxsl.sourceforge.net/ -- the home of FXSL XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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