Subject: Re: [xsl] 2 XML source From: "Simon Kelly" <kelly@xxxxxxxxxx> Date: Wed, 12 Mar 2003 14:49:26 +0100 |
You could use a xsl transform to create xsl transforms for the files (Sure I've seen this in one of the books somewhere. I'll try to dig it out). If you (don't know how, if on unix I'd write a shell script to rip the names from the source directory) load the xml file names into an xml doc like <files> <file>030312_01.xml</file> .... .... <file>030312_100.xml</file> </files> Then write a simple transform that takes your main transform and inserts the names from the file. Then a simple script again that runs each of these files one at a time in the xslt engine of your choice. There may be a more elegant way, but I ain't got Jennis skill at this xsl stuff (yet :-) Cheers Simon - "If you can't do it on a command line, it's not worth doing" - Kelly ----- Original Message ----- From: "David Alcantara" <wwwdavid@xxxxxx> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Sent: Wednesday, March 12, 2003 2:34 PM Subject: AW: [xsl] 2 XML source Thank you, but it´s not so simple. :-( every day i get approx. 100 XML files like 030312_01.xml (XML name = date+position) and i want to have only one XSL :-) Because every day other application creates 100's of xml files from which i need to filter some data out of these files. As you said in your mail that to incorporate the xml file names into the XSL File, i think in my case it is difficult to type all the file names into the XSL File. So in this case I request some other solution which suite my need given above. maybe is easily make a C program who integreate the 100 xml files in other one. Is there a way to make C or C++ program. Regards david -----Ursprüngliche Nachricht----- Von: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]Im Auftrag von Jarkko Moilanen Gesendet: Mittwoch, 12. März 2003 12:40 An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Betreff: Re: [xsl] 2 XML source On Wed, 12 Mar 2003, David Alcantara wrote: > Hi, > > i need to make a new XML file from 2 diferent XML source. > It´s possible? > > Regards > david > > I´m working with xalan 1.4.0 Yes it is and simple. =) Use document() function. For example: <xsl:value-of select="document('source.xml')/XPath"/> would look inside a file source.xml and traverse the tree by the given XPath. For more information see: http://www.w3.org/TR/xslt#document Cheers, Jarkko. > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > **************************************************************** Jarkko Moilanen "Erehtyminen on inhimillista, Researcher mutta todella suuret mokat jm60697@xxxxxx vaativat tietokoneen käyttöä." www.uta.fi/~jm60697 GSM: +358 50 3766 927 **************************************************************** * ITCM | Information Technology and Crisis Management * http://www.itcm.org **************************************************************** XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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