Subject: AW: [xsl] Syntax Problem From: "David Alcantara" <wwwdavid@xxxxxx> Date: Tue, 18 Mar 2003 14:33:04 +0100 |
I think it´s not the same. I need a variable to indicate the source file and another variable to indicate the Tag element. The variable v_Tag contain a string like "root/tagname", how can i convert the string? Regards david -----Ursprüngliche Nachricht----- Von: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]Im Auftrag von David Carlisle Gesendet: Dienstag, 18. März 2003 13:40 An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Betreff: Re: [xsl] Syntax Problem <xsl:copy-of select="document($v_file)//$v_Tag"/> That syntax is correct so long as $v_Tag contains a node set but it is the same as <xsl:copy-of select="$v_Tag"/> and would just copy the node set in the variable, If $v_Tag contains a string then it is not correct as it would be the same as <xsl:copy-of select="document($v_file)//'abc'"/> which would not be valid XPath. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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