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Subject: Re: [xsl] How to Process when Row data could be either elements or attributes From: Imrran Wahid <devguy2003@xxxxxxxxx> Date: Thu, 20 Mar 2003 13:50:16 -0800 (PST) |
I have found what I was doing wrong. However I cannot
explain why it was wrong. Maybe one of you can help.
I was modifying the follwing two templates:
> <xsl:template match="//Fruits/*[count(./*) >
> 0]/*">
> <tr>
> <xsl:apply-templates select="*"/>
> </tr>
> </xsl:template>
>
> <xsl:template match="*">
> <td>
> <xsl:value-of select="normalize-space(text())"/>
> </td>
> </xsl:template>
>
to
<xsl:template match="//Fruits/*[count(./*) > 0]/*">
<tr>
<xsl:apply-templates select="*|@*"/>
</tr>
</xsl:template>
<xsl:template match="*|@*">
<td>
<xsl:value-of select="normalize-space(text())"/>
</td>
</xsl:template>
The problem seemed to have been the 'text' function.
It does not seem to return the value of an attribute
node. Is this correct? When I added the following line
to the second template, the attributes' data was
retrieved into the table:
<xsl:value-of select="."/>
I can have both statements in this template without
worry, because the row will never have both elements
and attributes at the same time.
Imrran
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