Subject: Re: [xsl] how to insert the *complete* content of a node From: danilo <danilo_xml@xxxxxxxx> Date: 21 Mar 2003 15:56:48 +0000 |
> > uh oh ... i'm confused again. i thought "node()" explicitly > did *not* match attribute nodes, but only > > 1) elements > 2) text > 3) comments > 4) processing instructions > > was the original poster concerned about attributes as well? > Actually I do concern about attributes, so the proposed solution did not fit at all with what I need (but thanks a lot anyway!!) So I'm still trying with some other solution. Ah the: <xsl:template match="mytag"> <xsl:copy> <xsl:copy-of select="*|@*"/> </xsl:copy> </xsl:template> Still does not work. I Do not want to print the outer tag (mytag in the example) And I don't know how many level deep is the inner tree!!! There could be situations like: <mytag>blabla <foo attr1="aaa">some text <bar attr3="bb"> other text</bar> blabla </foo> <anything/> </mytag> and what I need is *all* the text betweem <mytag> and </mytag> unchanged!! bye Danilo. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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