Subject: Re: [xsl] xpath question From: florian <csshsh@xxxxxxxxxxxxxxx> Date: 27 Mar 2003 18:41:02 +0100 |
ah! i think i figured it out: i wonder if there is a more nice way though group/*[local-name() = $field] i set the field variable to the field attribute of the column node. is there a more elegant way though? ciao! florian On Don, 2003-03-27 at 18:07, florian wrote: > hi! > > i have a document xml doc like this: > > <root> > <group> > <apple>bla</apple> > <orange>bla</orange> > </group> > <group> > <apple>bla</apple> > <orange>bla</orange> > </group> > > <order> > <column name="orange" /> > <column name="apple" /> > </order> > </root> > > i would like to do the following: im going though all the column nodes > and would like to access the group nodes where the column attribute name > and the group node name match up. > > basically i can just not think of a way to do that in xpath.. anybody > got an tip? how can i say in xpath that it should get the node with > the name in @name and not just access the name attribute of a group > node.. > > thanks alot! > > ciao! > florian > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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