Subject: RE: [xsl] simple matching problem From: "Michael Kay" <mhk@xxxxxxxxx> Date: Sat, 29 Mar 2003 09:39:24 -0000 |
> Here's another: This seems to find the element node where > @task = 1, but it doesn't actually write out the value of > @task. Why? It just writes out: @TASK = > > Thanks- > Mac > > <xsl:param name="$nextTask" select="1" /> > > <xsl:if test="//*[@task=$nextTask]"> > @TASK = <xsl:value-of select="@task" /> > </xsl:if> > Your <xsl:if> tests whether an element exists satisfying certain conditions, but it doesn't make this element the context node. To achieve that, write: <xsl:for-each select="//*[@task=$nextTask]"> @TASK = <xsl:value-of select="@task" /> </xsl:for-each> Michael Kay Software AG home: Michael.H.Kay@xxxxxxxxxxxx work: Michael.Kay@xxxxxxxxxxxxxx XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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