Subject: [xsl] position() returns doubled result - what do i miss? From: jian <jian@xxxxxxxxxxxxxxxxxx> Date: Mon, 31 Mar 2003 15:50:05 +0900 |
i have : <?xml version="1.0" encoding="UTF-8" ?> <root> <item>item1</item> <item>item2</item> <item>item3</item> <item>item4</item> <item>item5</item> <item>item6</item> <item>item7</item> <item>item8</item> <item>item9</item> </root> to which i apply: <?xml version="1.0" encoding="UTF-8" ?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="html" version="4.01" encoding="UTF-8"/> <xsl:template match="/"> <xsl:apply-templates match="root/item"/> </xsl:template> <xsl:template match="item"> <xsl:value-of select="position()"/> <xsl:value-of select="."/> </xsl:template> </xsl:stylesheet> and for some reason i get : 2item1 4item2 6item3 8item4 10item5 12item6 14item7 16item8 18item9 what do i miss? jian XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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