RE: [xsl] XPath Axes

[Jarno.Elovirta@xxxxxxxxx]

Hi,

> How to convert following xml into xml output format
> using XPath Axes.

You mean XSLT?

> Input:
> ------
> <trow>
>       <cell>author 1</cell>
>       <cell>fname:</cell>
>       <cell>John</cell>
> </trow>
> <trow>
>       <cell/>
>       <cell>midname:</cell>
>       <cell>N.</cell>
> </trow>
> <trow>
>       <cell/>
>       <cell>sname:</cell>
>       <cell>Tippett</cell>
> </trow>
> 
> Output:
> -------
> <author id="1">
> <fname>John</fname>
> <midname>N.</midname>
> <sname>Tippett</sname>
> </author>

e.g.

<xsl:template match="*[trow]">
  <xsl:variable name="x" select="trow[cell[1]/text()]/cell[1]/text()" />
  <xsl:element name="{substring-before($x, ' ')}">
    <xsl:attribute name="id">
      <xsl:value-of select="substring-after($x, ' ')" />
    </xsl:attribute>
    <xsl:apply-templates select="*" />
  </xsl:element>
</xsl:template>

<xsl:template match="trow">
  <xsl:element name="{translate(cell[2], ':', '')}">
    <xsl:value-of select="cell[3]" />
  </xsl:element>
</xsl:template>

Cheers,

Jarno - Flesh Field: Prophecy (Assemblage 23 Remix)

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list