Re: [xsl] generate full xpath name to an attribute?

[Ray Tayek <rtayek@xxxxxxxxx>]

At 11:09 AM 4/3/03 +0100, you wrote:

> > i get: /input/Nodes/Node/Point3.1415926535897
> > what i want is: /input/Nodes/Node/Point@x (i think).
>
> You need to read the text as well as just copying code blindly.
> Jeni's code is doing a slightly different problem, the line above the
> code you've quoted says
>
>   Once we've outputted the information about the ancestor elements, we
>   want to round it off with information about the value of the current
>   node:
>
> So Jeni's outputting the value as well as the path, and surely it is
> clear enough that it ends with a value-of eslect="."  which you don't
> want.

yes, i got the following to work:

        <xsl:template name="foo">
                <xsl:for-each select="ancestor-or-self::*">
                        <xsl:text>/</xsl:text>
                        <xsl:value-of select="name()"/>
                </xsl:for-each>
                        <xsl:text>@</xsl:text>
                <xsl:value-of select="name()"/>
        </xsl:template>

and since i *know* that everything i am interested in is an attribute, i 
can make progress now.

> > and i will still have the subscript problem. as Node can occur multiple 
> times.
>
> But that isn't a problem as that FAQ page and other answers on this list
> have posted code to do that.

i will look for them.

thanks for your assustance.

---
ray tayek http://tayek.com/ actively seeking mentoring or telecommuting work
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