Subject: [xsl] How to test if a named attribute exists and put the name of that attribute in an generic way From: "Braumüller, Hans" <H.Braumueller@xxxxxxxxxxxx> Date: Mon, 7 Apr 2003 11:52:25 +0200 |
Hello, i am testing hardcoding following attribute refDB, if it not exists in the node $header, where in $header the attribute name corresponds to variable $colname, which is the attribute name in the xml-source. <xsl:if test="string($header[@name=$colname]/@refDB) != '' "> <xsl:attribute name="refDB"><xsl:value-of select="$header[@name=$colname]/@refDB"/></xsl:attribute> </xsl:if> xml-source: <col name="ktdbtr" title="Disposition Amount"></col> xml-properties: <header name="ktdbtr" inputType="text" refDB="Dispo" class="numberField" format="number" editable="0">Dispo Amount</header> I am trying to do this now in a more generic way calling a template, trying to test for all attributes if they exists in the header to output them with their values. like pseudo-code: <xsl:template name="outputAttribute"> <xsl:param name="attributeName"/> <xsl:param name="attributeValue"/> <xsl:if test="string($attributeValue) != '' "><xsl:attribute name="$attributeName"><xsl:value-of select="$attributeValue"/></xsl:attribute></xsl:if> -----------------------------------------------------------------------^ not possibly because of xsl-language either something like <xsl:attribute name="name($attributeValue)"> </xsl:template> Thanks, Hans Braumüller PEACE IS WAR IS PEACE http://plutokratie.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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