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Subject: [xsl] How to test if a named attribute exists and put the name of that attribute in an generic way From: "Braumüller, Hans" <H.Braumueller@xxxxxxxxxxxx> Date: Mon, 7 Apr 2003 11:52:25 +0200 |
Hello,
i am testing hardcoding following attribute refDB, if it not exists in the node $header, where in $header the attribute name corresponds to variable $colname, which is the attribute name in the xml-source.
<xsl:if test="string($header[@name=$colname]/@refDB) != '' ">
<xsl:attribute name="refDB"><xsl:value-of select="$header[@name=$colname]/@refDB"/></xsl:attribute>
</xsl:if>
xml-source:
<col name="ktdbtr" title="Disposition Amount"></col>
xml-properties:
<header name="ktdbtr" inputType="text" refDB="Dispo" class="numberField" format="number" editable="0">Dispo Amount</header>
I am trying to do this now in a more generic way calling a template, trying to test for all attributes if they exists in the header to output them with their values.
like pseudo-code:
<xsl:template name="outputAttribute">
<xsl:param name="attributeName"/>
<xsl:param name="attributeValue"/>
<xsl:if test="string($attributeValue) != '' "><xsl:attribute name="$attributeName"><xsl:value-of select="$attributeValue"/></xsl:attribute></xsl:if>
-----------------------------------------------------------------------^
not possibly because of xsl-language either something like <xsl:attribute name="name($attributeValue)">
</xsl:template>
Thanks,
Hans Braumüller
PEACE IS WAR IS PEACE
http://plutokratie.com
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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