Subject: RE: [xsl] Identity transform of stylesheet From: "Michael Kay" <mhk@xxxxxxxxx> Date: Mon, 7 Apr 2003 19:18:02 +0100 |
> I need to perform an identity transform on a stylesheet to > add an attribute to each and every LRE. The stylesheet(s) > are of the form: > > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > <xsl:include href="foo.xsl"/> > <xsl:template match="/"> > <xsl:apply-templates/> > </xsl:template> > </xsl:stylesheet> > > The issue is performing the transform after all of the > includes/imports of the xsl have been processed, rather that > just the 6 line xml document. If the above is your source document, then it is just data, so there is no sense in which any xsl:include and xsl:import elements are going to be "processed, other than being processed in the same way as any other element in the source document. If you want to apply the same transformation to the above document and to all the documents referenced (recursively) by xsl:include and xsl:import elements you can do: <xsl:template match="xsl:stylesheet | xsl:transform"> <xsl:apply-templates select="." mode="add-attributes"/> <xsl:for-each select="document(xsl:include/@href | xsl:import/@href)"> <xxx:result-document href="."> <xsl:apply-templates select="*"/> </xxx:result-document> </xsl:for-each> </xsl:template> Where xxx:result-document is an extension element provided by your processor to produce multiple output files. Michael Kay Software AG home: Michael.H.Kay@xxxxxxxxxxxx work: Michael.Kay@xxxxxxxxxxxxxx > Ideally, I would > like to be able to take the transformer object and process > that as xml... as that would be the entire stylesheet, but of > course Im more than likely talking rubbish here :) Yes, there's no way you can reverse compile a transformer object to produce XML. Michael Kay Software AG home: Michael.H.Kay@xxxxxxxxxxxx work: Michael.Kay@xxxxxxxxxxxxxx XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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