Re: [xsl] anyone can solve it

[Nathaniel Brett Stoddard <nstoddar@xxxxxxxxx>]

Hi,

Warning: this is a newbie answer, but here goes ...

I think you could 1) create a parameter or variable, 2) sort the row elements by its year
parameter's value and 3) as you iterate over the row elements, compare the value of the immediate
row's year attribute value to the value you previously (or initialized) put into the parameter or
variable from step (1) ... depending on the comparison you would write out the year and set the
value of your variable/parameter accordingly so you can compare and see when the next year comes
along.  You would do all this, of course, probably within the "record" match tag (or whatever the
technical name for it is called).

If you were looking for some actual xslt snippet, sorry :)  Hope this helps you along on the right
track though.  The rest as I see it is just a matter of syntax, if I'm not mistaken.

Nathaniel Stoddard

--- Cheung Tin Po <timothy298@xxxxxxxxxxx> wrote:
> hi expert,
> 
> i get an xml file like that
> <record>
> <row year="2000" month="1" thedata="xyx" />
> <row year="2000" month="2" thedata="xyx" />
> <row year="2000" month="3" thedata="xyx" />
> <row year="2000" month="4" thedata="xyx" />
> <row year="2000" month="5" thedata="xyx" />
> <row year="2001" month="1" thedata="xyx" />
> <row year="2000" month="3" thedata="xyx" />
> <row year="2002" month="1" thedata="xyx" />
> </record>
> 
> i want to use xsl the to trasform the output as html with the following 
> result
> 
> 2000 / 1  : xyx
>        2  : xyx
>        3  : xyx
> 2001 / 1  : xyx
>        3  : xxx
> ...
>        9  : sss
> 2002 / 1  : xxx
>        2  : xxx
> 
> 
> i want the year to show once only...  but i really dont know hoe to do that  
>   as i dont know how to remember the value of year in the previous elements
> 
> From Timothy
> 
> 
> 
> 
> 
> 
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