Subject: Re: [xsl] selecting the nearest preceding sibling From: Nicolas Mazziotta <nicolas.mazziotta@xxxxxxxxx> Date: Tue, 13 May 2003 15:47:12 +0200 |
Hello , My XML file is below
XML file ------------ <rootelem>
<tag> --- node 1 <a>1</a> <b>2</b> <c>3</c> <d>4</d> </tag>
<tag> --- node 2 <b>5</b> <c>6</c> <d>7</d> </tag>
<tag> --- node 3 <a>8</a> <b>9</b> <c>10</c> <d>11</d> </tag>
<tag> --- node 4 <b>12</b> <c>13</c> <d>14</d> </tag>
<tag> --- node 5 <b>15</b> <c>16</c> <d>17</d> </tag>
</rootelem> ---------------------- I want to write **a XPATH expression which will select the nearest preceding sibling , which contains a particular element ( <a> in this example) ** . I do not want preceding sibling which do not contain the <a> tag (also the tag <a> should be nearest to the context node)
for e.g. if the context node is node 5 , the XPATH expression which will select node 3(because it contains element <a>) or for e.g. if the context node is node 2 , the XPATH expression will select node 1(because it contains element <a>)
I am trying with preceding-sibling::tag ??
Can somebody suggest a solution?
Regards, Mukul
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maybe this? was that what you meant?
1234
567 1 2 3 4
891011 1 2 3 4
121314 8 9 10 11
151617 8 9 10 11
-- +----------------------------+ |Nicolas Mazziotta | |Aspirant au doctorat | |Linguistique française | |Département d'études romanes| |Université de Liège | +----------------------------+ |04/3665382 | |nicolas.mazziotta@xxxxxxxxx | +----------------------------+
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