Subject: [xsl] How to open a page in xsl From: Archana Rao <archana_heroor@xxxxxxxxx> Date: Mon, 22 Sep 2003 14:40:36 -0700 (PDT) |
Hello everybody, JSP passes the username to my xsl, i know what the user name is that is, in my xsl i have <xsl:param name="username"/> So i know what the username is, now my problem is i am trying to open up www.yahoo.com if the username is xyz@xxxxxxxxx and www.hotmail.com if the username has xyz@xxxxxxxxxxxx I know i can use <xsl:if test="contain($username, 'yahoo')"> to check for the username, but then i don't know how to specify in the <xsl:if> to open up www.yahoo.com. Hope you understood my problem. TIA, Archana __________________________________ Do you Yahoo!? Yahoo! SiteBuilder - Free, easy-to-use web site design software http://sitebuilder.yahoo.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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