Re: [xsl] Attempting *not* to copy certain nodes

["J.Pietschmann" <j3322ptm@xxxxxxxx>]

3rett 3onfield wrote:
> <MapSecuritiesResult>
>   <Security>
>   <Outcome>RequestError</Outcome>
...
> I want to copy the <Security> nodes in which the Outcome was Success and 
> want not to copy the ones in which the Outcome was Request Error.

> The XSLT file I've used is based on an earlier discussion on this list:
> http://www.biglist.com/lists/xsl-list/archives/200307/msg01390.html
>
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet version="1.0" 
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
> <xsl:output method="text" version="1.0" encoding="UTF-8" indent="yes"/>

The "indent" attribute has no effect for text output.

> <xsl:template match="Root">
>    <xsl:apply-templates select="MapSecuritiesResult"/>
> </xsl:template>
There is no node named "Root" in your XML source.

> <xsl:template match="Security">
>    <xsl:copy>
>       <xsl:apply-templates select="Outcome[Success]"/>
>    </xsl:copy>
> </xsl:template>

This will always copy any Security element, and apply templates
to the Outcome child elements which itself have a Success child
element. In your XML, the Outcome elements contain the *text*
"Succes" (or other text), but no child elements. This means you wont
get any output here. The default templates will provide you which
some whitespace and possibly other text from outside the Security
elements.

Try
  <?xml version="1.0" encoding="UTF-8"?>
  <xsl:stylesheet version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
    <xsl:output method="text" version="1.0" encoding="UTF-8" indent="yes"/>
    <xsl:template match="/">
      <xsl:copy-of select="Security[Outcome='Success']"/>
    </xsl:template>
  </xsl:stylesheet>
which should be a bit closer to your expectations. This provides literal
copies of all Security elements (with all children) which have an Outcome
child element containing the text "Success". You'll probably want to have
something else but use this as a start for refinement.

> Obviously, it's not working or I wouldn't be asking for help. Sorry if 
> I've not searched the FAQ properly.

Try starting to learn XSLT systematically, using simpler transformations,
and perhaps an environment which visualizes XPath selections and how
templates are applied (search for "XPath visualizer").

J.Pietschmann

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