Re: Antw: [xsl] Merging two xml files

["Agnes Kielen" <agnes.kielen@xxxxxxx>]

Hi,
You can better send questions to the xsl-list. In this way everybody can
learn from the questions and answers and everyone can answer!

Change (untested):
<xsl:variable name="pin" select="$emps//employee[@id = $id]/@pincode"/>
<employee>
     <xsl:if test="$pin>
          <xsl:attribute name="pincode">
               <xsl:value-of select="$pin"/>
          </xsl:attribute>
     </xsl:if>
     <!-- copy the child nodes -->
          <xsl:copy-of select="*"/>
         <!-- copy the address -->
         <xsl:copy-of select="$emps//employee[@id =$id]/address"/>
  </employee>

Variable $pin will test to true if it exists otherwise it will be false.

Cheers,
Agnes



----- Original Message ----- 
From: "Arulraj" <p_arulraj@xxxxxxxxx>
To: <agnes.kielen@xxxxxxx>
Sent: Tuesday, January 13, 2004 11:08 AM
Subject: Re: Antw: [xsl] Merging two xml files


> Hi Agnes,
>  This works fine. I have one more doubt. If I have
> pincode attribute in second.xml, then In Ouput should
> have <employee pincode=""> otherwise I no need to have
> pincode attribute just <employee> is enough.
>
> So I need to check pincode is appear in second XML
> then adding it to resultant <employee> element.
>
> If you got an idea!
> Please reply me.
>
> Thanking you,
> Arul
>
> --- agnes.kielen@xxxxxxx wrote:
> > Hi Arul,
> >
> > <?xml version="1.0"?>
> > <xsl:stylesheet
> > xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
> > version="1.0">
> >   <xsl:output method="xml" indent="yes"/>
> >   <!-- load the merge file -->
> >   <xsl:variable name="emps"
> > select="document('employeeAddresses.xml')"/>
> >   <xsl:template match="/">
> >      <employees>
> > <xsl:for-each select="employees/employee"> <!--
> > cache the employee's ID --> <xsl:variable
> > name="id" select="@id"/> <!-- copy the pincode of
> > the second XML --> <employee
> > pincode="{$emps//employee[@id = $id]/@pincode}">
> >         <!-- copy the child nodes -->
> >         <xsl:copy-of select="*"/>
> > <!-- copy the address -->
> >         <xsl:copy-of select="$emps//employee[@id =
> > $id]/address"/>
> >     </employee>
> >    </xsl:for-each>
> > </employees>
> > </xsl:template>
> > </xsl:stylesheet>
> >
> > I changed the
> > <xsl:variable name="id"><xsl:value-of
> > select="@id"/></xsl:variable>
> > in <xsl:variable name="id" select="@id"/>
> > This is shorter to write, easier to read and you
> > don't create a RTF.
> > Furhtermore I changed child::* in *.
> >
> > I select the correct nodes from employeeAddress.xml
> > with the help of the following pattern:
> > $emps//employee[@id = $id].
> > In english this means something like select those
> > employee from the second file from which the
> > id-attribute is equal to the current id in the main
> > xml.
> >
> >
> > Cheers,
> > Agnes
> >
> >
> >
> >
> >
> >
> >
> >  XSL-List info and archive:
> > http://www.mulberrytech.com/xsl/xsl-list
> >
>
>
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