Subject: RE: [xsl] Problem setting variable in if statement From: "Martinez, Brian" <brian.martinez@xxxxxxxxxxx> Date: Mon, 2 Feb 2004 13:00:15 -0700 |
> From: Johnson, Kaerstin [mailto:johns218@xxxxxxxxx] > Sent: Monday, February 02, 2004 12:03 PM > To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Problem setting variable in if statement > > > I am very new to xsl/xslt and have a basic problem. I am > setting a style > sheet color based on a condition. > I'd like the color to be a variable value, like > <xsl:variable name="statColor" select="#33cc33"> > and set this variable in the if/choose condtion. > Then recall it like > <span style="color:{$statColor}"><xsl:value-of select="status"></span> You'll still need to use the xsl:choose construct, but just move it inside the xsl:variable element: <xsl:variable name="statColor"> <xsl:choose> <xsl:when test="status='undelivered'">#ff0000</xsl:when> <xsl:when test="status='inprogress'">#33cc33</xsl:when> <xsl:when test="status='delivered'">#0033ff</xsl:when> <xsl:when test="status='escalated'">#ffff33</xsl:when> <xsl:otherwise>#000000</xsl:otherwise> </xsl:choose> </xsl:variable> Then reference $statColor as you have it. If you use $statColor only once, it may not be any more efficient, but it's easier to read. hth, b. | brian martinez brian.martinez@xxxxxxxxxxx | | lead gui programmer 303.357.3548 | | cheap tickets, part of trip network fax 303.357.3380 | | 6560 greenwood plaza blvd., suite 400 englewood, co 80111 | | cendant travel distribution services http://www.cheaptickets.com/ | XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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