Subject: RE: [xsl] translate From: "M. David Peterson" <m.david@xxxxxxxxxx> Date: Wed, 24 Mar 2004 08:17:34 -0700 |
You also need to remember that translate() is not a regex-styled pattern matching function but instead a way to match individual characters in the second position of the function to a string in the first position and replace them with the character within the third position function found in the same numerical position of the second position of the function. Or in other words translate('cat', 'abcdefghijklmnopqrstuvwxyz', 'ABCDEFGHIJKLMNOPQRSTUVWXYZ') would return 'CAT'. What it seems like you are trying to do (replace each instance of one entity with the value of another) is a much more complicated process that requires using a recursive named-template method. Examples of this method can be found all over the archives. Best of luck! <M:D/> -----Original Message----- From: David Carlisle [mailto:davidc@xxxxxxxxx] Sent: Wednesday, March 24, 2004 7:35 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] translate > How can I make this work? translate() takes three strings as arguments you have given a Node set as the first, which is OK, it will take the string value of that node, but your second two arguments are just floating characters, so a syntax error, XPath strings have to be in "" or '' so you want translate(EPAPER,'-','–') David -- http://www.dcarlisle.demon.co.uk/matthew ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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