Subject: RE: [xsl] Problem with msxsl:node-set From: "Kenny Akridge" <kenny@xxxxxxxxxxxxxxxxx> Date: Sat, 27 Mar 2004 19:28:59 -0500 |
I think I just figured it out right after I submitted this. [number($begin)] seems to be working. -----Original Message----- From: Kenny Akridge [mailto:kenny@xxxxxxxxxxxxxxxxx] Sent: Saturday, March 27, 2004 7:25 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] Problem with msxsl:node-set I have this variable, whose internal workings aren't very important: <xsl:variable name="uniqueClassDates"> <xsl:for-each select="ArrayOfAttendance/Attendance/ClassDate[number(substring(.,1,4)) > 0001 and not(. = preceding::ClassDate)]"> <xsl:element name="date"> <xsl:value-of select="."/> </xsl:element> </xsl:for-each> </xsl:variable> Which holds this value: <date>2004-01-10T00:00:00.0000000-05:00</date> <date>2004-01-11T00:00:00.0000000-05:00</date> <date>2004-01-12T00:00:00.0000000-05:00</date> The problem occurs while I am running this comparison: <xsl:if test="msxsl:node-set($uniqueClassDates)/date[$begin] = ClassDate"> In this case, $begin will be 1, 2 or 3. However, if I pass ClassDate with any value that is contained in $uniqueClassDates, it always returns true. How can I limit the logic to only return true when the $begin position of date matches ClassDate? Here is entire template: <xsl:template name="indexAttendanceCells"> <xsl:param name="begin"/> <xsl:param name="end"/> <xsl:choose> <xsl:when test="$begin > $end"></xsl:when> <xsl:otherwise> <xsl:variable name="attended"> <xsl:if test="msxsl:node-set($uniqueClassDates)/date[$begin] = ClassDate"> <xsl:text>true</xsl:text> </xsl:if> </xsl:variable> <xsl:choose> <xsl:when test="$attended = 'true'"> <td> X </td> </xsl:when> <xsl:otherwise> <td>   </td> <xsl:call-template name="indexAttendanceCells"> <xsl:with-param name="begin" select="$begin + 1"/> <xsl:with-param name="end" select="$end"/> </xsl:call-template> </xsl:otherwise> </xsl:choose> </xsl:otherwise> </xsl:choose> </xsl:template>
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