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Subject: RE: [xsl] Recursive selection, elegantly From: "Stephen Tredrea" <stephen.tredrea@xxxxxxxxxxxxx> Date: Mon, 7 Jun 2004 09:32:31 +0200 |
Thanks everyone... noted use of 'variable' to add to my usage as well as
current(), which solves the problem perfectly. Final soln (in effect):
<xsl:template match="menu" mode="main_menu">
<table>
<tr>
<xsl:apply-templates select="//*[@about = current()/item/@resource]"
mode="menu_item" />
</tr>
</table>
</xsl:template>
<xsl:template match="*" mode="menu_item">
<td>
<a href="{@about}">
<xsl:value-of select="name" />
</a>
</td>
</xsl:template>
-----Original Message-----
From: Marcus Andersson [mailto:marcus@xxxxxxxxxx]
Sent: 06 June 2004 01:48 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Recursive selection, elegantly
How about this one:
<xsl:template match="/root">
<html>
<head>
<title/>
</head>
<body>
<table>
<tr>
<xsl:apply-templates select="menu/item"/>
</tr>
</table>
</body>
</html>
</xsl:template>
<xsl:template match="item">
<xsl:variable name="resource" select="/root/*[@about =
current()/@resource]"/>
<td><a href="{$resource/@about}"><xsl:value-of
select="$resource/name"/></a></td>
</xsl:template>
/Marcus
Stephen Tredrea wrote:
> Thanks Mukul for your response (and showing me how to use {} - that's new
to
> me). Unfortunately your solution doesn't cater for instances where:
>
> a) an item in the menu is not a 'page', or
> b) only a selection of resources constitute the menu
>
> ...which is why I want to build the menu from the menu node.
>
> My apologies for providing an insufficient sample, here's alternative xml:
>
> <?xml version="1.0" encoding="UTF-8"?>
> <root>
> <menu ref="main_menu">
> <item resource="/"/>
> <item resource="/who_we_are"/>
> <item resource="/contact_us"/>
> <item resource="/mulberries"/>
> </menu>
> <page about="/">
> <name>Home</name>
> </page>
> <page about="/who_we_are">
> <name>About us</name>
> </page>
> <page about="/contact_us">
> <name>Contact us</name>
> </page>
> <page about="/disclaimer">
> <name>Disclaimer</name>
> </page>
> <category about="/mulberries">
> <name>Top fruit</name>
> </category>
> </root>
>
> Note that in this sample I don't want 'Disclaimer' in the menu.
>
> This XSL below works but... I think it's clunky and I don't understand why
> the simpler version I provided in my prior example doesn't work.
>
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>
> <xsl:output method="html" version="1.0" encoding="UTF-8" indent="yes"/>
>
> <xsl:template match="/">
> <xsl:apply-templates select="//menu[@ref='main_menu'"
mode="main_menu"
> />
> </xsl:template>
>
> <xsl:template match="menu" mode="main_menu">
> <table>
> <tr>
> <xsl:apply-templates select="item" />
> </tr>
> </table>
> </xsl:template>
>
> <xsl:template match="item">
> <xsl:param name="resource"><xsl:value-of select="@resource"
> /></xsl:param>
> <xsl:apply-templates select="/root/*[@about = $resource]"
> mode="menu_item" />
> </xsl:template>
>
> <xsl:template match="*" mode="menu_item">
> <td>
> <a href="{@about}">
> <xsl:value-of select="name"/>
> </a>
> </td>
> </xsl:template>
> </xsl:stylesheet>
>
> Regard, Stephen
>
> -----Original Message-----
> From: Mukul Gandhi [mailto:mukul_gandhi@xxxxxxxxx]
> Sent: 06 June 2004 10:02 AM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] Recursive selection, elegantly
>
>
> Hi Stephen,
> Given the XML -
>
> <?xml version="1.0" encoding="UTF-8"?>
> <root>
> <menu ref="main_menu">
> <item resource="/"/>
> <item resource="/who_we_are"/>
> <item resource="/contact_us"/>
> <item resource="/disclaimer"/>
> </menu>
> <page about="/">
> <name>Home</name>
> </page>
> <page about="/who_we_are">
> <name>About us</name>
> </page>
> <page about="/contact_us">
> <name>Contact us</name>
> </page>
> <page about="/disclaimer">
> <name>Disclaimer</name>
> </page>
> </root>
>
> The following XSL -
>
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> <xsl:output method="html" version="1.0"
> encoding="UTF-8" indent="yes"/>
>
> <xsl:template match="/root">
> <html>
> <head>
> <title/>
> </head>
> <body>
> <table>
> <tr>
> <xsl:apply-templates select="page"/>
> </tr>
> </table>
> </body>
> </html>
> </xsl:template>
>
> <xsl:template match="page">
> <td>
> <a href="{@about}">
> <xsl:value-of select="name"/>
> </a>
> </td>
> </xsl:template>
>
> </xsl:stylesheet>
>
> produces output -
>
> <html>
> <head>
> <title></title>
> </head>
> <body>
> <table>
> <tr>
> <td><a href="/">Home</a></td>
> <td><a href="/who_we_are">About us</a></td>
> <td><a href="/contact_us">Contact us</a></td>
> <td><a href="/disclaimer">Disclaimer</a></td>
> </tr>
> </table>
> </body>
> </html>
>
> Regards,
> Mukul
>
> --- Stephen Tredrea <stephen.tredrea@xxxxxxxxxxxxx>
> wrote:
>
>>Any suggestion on getting this to work? I can do it
>>in four steps but not in
>>three as attempted here!
>>
>>Thanks, Stephen
>>
>>XML (snippet):
>>
>> <menu ref="main_menu">
>> <item resource="/" />
>> <item resource="/who_we_are" />
>> <item resource="/contact_us" />
>> <item resource="/disclaimer" />
>> </menu>
>>
>> <page about="/">
>> <name>Home</name>
>> </page>
>>
>> <page about="/who_we_are">
>> <name>About us</name>
>> </page>
>>
>> ...etc...
>>
>>XSL (snippet):
>>
>> <xsl:template match="/">
>> <xsl:apply-templates
>>select="//menu[@ref='main_menu'" mode="main_menu"
>>/>
>> </xsl:template>
>>
>> <xsl:template match="menu" mode="main_menu">
>> <table>
>> <tr>
>> <xsl:apply-templates select="//*[@about =
>>item/resource]"
>>mode="menu_item" />
>> </tr>
>> </table>
>> </xsl:template>
>>
>> <xsl:template match="*" mode="menu_item">
>> <td>
>> <xsl:element name="a">
>> <xsl:attribute name="href"><xsl:value-of
>>select="@about"
>>/></xsl:attribute>
>> <xsl:value-of select="name" />
>> </xsl:element>
>> </td>
>> </xsl:template>
>>
>>Required HTML:
>>
>> <table>
>> <tr>
>> <td><a href="/">Home</a></td>
>> <td><a href="/who_we_are">About us</a></td>
>> ...etc...
>> </tr>
>> </table>
>>
>>
>>
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>
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