Subject: Re: [xsl] Re: [xslt transform & grouping] Using the Muenchian Method? From: David Carlisle <davidc@xxxxxxxxx> Date: Tue, 5 Oct 2004 16:06:51 +0100 |
> Use this XSLT to genterate new XML file by using specified XML input > file: clearly that will generate an error as it uses a kety that is not defined, as I pointed out in the message that you quoted. As such it will generate no output. If you fix that then you will get no error and if you fix <xsl:param name="filter" select="food"></xsl:param> to have 'food' then you will get the output that I also posted in that message, assuming you have a conforming processor. If you leave $filter with that value you'll just get an empty Documents element as $filter would be an empty node set as previously explained. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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