Subject: [xsl] counting nodes From: "Katrin Schoenherr" <k_schoenherr@xxxxxx> Date: Wed, 6 Oct 2004 12:12:04 +0200 |
Hallo, thanks a lot for answering my last question. Now, i have to count different nodes and i can't find a solution. Perhaps someone can point me to. I want to count all descenders and all ascenders. In this example the solution is 2 descenders and 2 ascenders: <output> <features> <feature name="descender-g" /> <feature name="descender-y" /> <feature name="ascender-h" /> <feature name="ascender-l" /> </features> </output> Thats my try: <xsl:for-each select="//feature"> <xsl:value-of select="substring-before(@name,'-')='descender'"/> </xsl:for-each> The function substring() is working. But count(substring(...)) not. I have to count the true results. How can i solve this problem? Thanks, Katrin.
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