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Subject: [xsl] counting nodes From: "Katrin Schoenherr" <k_schoenherr@xxxxxx> Date: Wed, 6 Oct 2004 12:12:04 +0200 |
Hallo,
thanks a lot for answering my last question.
Now, i have to count different nodes and i can't find a solution.
Perhaps someone can point me to.
I want to count all descenders and all ascenders.
In this example the solution is 2 descenders and 2 ascenders:
<output>
<features>
<feature name="descender-g" />
<feature name="descender-y" />
<feature name="ascender-h" />
<feature name="ascender-l" />
</features>
</output>
Thats my try:
<xsl:for-each select="//feature">
<xsl:value-of select="substring-before(@name,'-')='descender'"/>
</xsl:for-each>
The function substring() is working. But count(substring(...)) not.
I have to count the true results. How can i solve this problem?
Thanks, Katrin.
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