Subject: [xsl] Copy one element from one xml file to another From: Nishi Bhonsle <nishi.bhonsle@xxxxxxxxxx> Date: Thu, 21 Oct 2004 14:13:30 -0700 |
Hi: I have xml1 based on xsd1 and xml2 based on xsd2. I want to copy the value of the attribute "name" of the "transport" element from xml1 to xml2. Consider xml1: <?xml version = '1.0' encoding = 'UTF-8'?> <applet locale="en" ...................> <transport name="jrmp"/><transport name="codebase"/> .... ... ... </applet> ---------------------------------------- Consider xml2: <disco:configuration xmlns:disco=......................... xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation=............... > .... .... <plus helpSet="help"> <transport name="jrmp"/> <transport name="http"/> </plus> </disco:configuration> ----------------------------------------- I noticed the following xsl would do the job in the sense, it outputs the correct value -- <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:disco="http://www.oracle.com/discoverer/configuration" xmlns:fo="http://www.w3.org/1999/XSL/Format"> <xsl:output method="xml" encoding="ISO-8859-1" indent="yes" /> <xsl:template match="transport"> <xsl:call-template name="copy"/> </xsl:template> <xsl:template name="copy"> <xsl:copy> <xsl:apply-templates select="@*" mode="copy" /> <xsl:apply-templates/> <xsl:value-of select="text()"/> </xsl:copy> </xsl:template> </xsl:stylesheet> ------------------------------------------------- How can I thereafter replace the value for the transport element in xml2 with the values I have from the above transform? Thanks, Nishi.
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