Subject: [xsl] XSLT - update attribute with new value From: Ann Marie Rubin <Annmarie.Rubin@xxxxxxx> Date: Fri, 05 Nov 2004 09:36:39 -0500 |
Hello David, Thanks very much for your help. At least I now know that this is possible. My stylesheet outputs the xml file unchanged. It does not replace the value with the value of $value. I am probably doing something wrong with the variable declaration but don't see the problem. The stylesheet looks like this: Do you see what might be wrong? Thanks very much, Ann Marie <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output indent="yes" method="xml"/> <xsl:variable name="attr" select="deployment-version"/> <xsl:variable name="value" select='TEST'/> <xsl:param name="attr"/> <xsl:param name="value"/> <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> <xsl:template match="@*" priority="10"> <xsl:attribute name="{name()}"> <xsl:choose> <xsl:when test="name()=$attr"><xsl:value-of select="$value"/></xsl:when> <xsl:otherwise><xsl:value-of select="."/></xsl:otherwise> </xsl:choose> </xsl:attribute> </xsl:template> </xsl:stylesheet>
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