Subject: RE: [xsl] RE: [Bu posta banka disindan gelmekte olup gerektiginde teyit alinmalidir.] - [xsl] find the sum over distinct nodes - Sender blacklisted From: Osman Çınar Eren <Cinar.Eren@xxxxxxxxxxxxx> Date: Fri, 19 Nov 2004 09:20:58 +0200 |
hi, my problem seems to be related to multiple level grouping. there is a nice answer in your link. however my question is more complex; My second level grouping is not in the same level. My input data : <value> <B> <key>aa</key> <value> <v1>aa</v1> <v2>110</v2> </value> </B> <B> <key>bb</key> <value> <v1>bb</v1> <v2>10</v2> </value> </B> <B> <key>cc</key> <value> <v1>cc</v1> <v2>60</v2> </value> </B> <C>002</C> </value> <value> <B> <key>bb</key> <value> <v1>bb</v1> <v2>40</v2> </value> </B> <B> <key>cc</key> <value> <v1>cc</v1> <v2>200</v2> </value> </B> <C>002</C> </value> <value> <B> <key>dd</key> <value> <v1>dd</v1> <v2>60</v2> </value> </B> <C>001</C> </value> my keys: <xsl:key name="categorise" match="value" use="C"/> <xsl:key name="dkey" match="value" use="v1"/> two groupings are as follows: first group according to C values of 'value' elements: <xsl:for-each select="value[generate-id()= generate-id(key('categorise',C)[1])]"> <xsl:call-template name="mytemplate"> <xsl:with-param name="ZZZ" select="$ZZZ" /> </xsl:call-template> </xsl:for-each> in my template: > <xsl:for-each select="$ZZZ/B/value[generate-id(.) = > generate-id(key('dkey', v1))]"> > <xsl:variable name="miktar" select="sum(key('dkey', > v1)/v2)"/> > <fo:table-row> > <fo:table-cell> > <fo:block text-align="left" font-size="8pt" > > <xsl:value-of select='format-number($miktar, > "###,###.00")'/> > </fo:block> > </fo:table-cell> > </fo:table-row> > </xsl:for-each> so how can i move the first key value into the second one as it is given in the link below?(the two keys are in different levels in the XML) i am not sure if i could tell my problem, if it is not enough i can go deeper. thanks in advance. best regards... -----Original Message----- From: JBryant@xxxxxxxxx [mailto:JBryant@xxxxxxxxx] Sent: Thursday, November 18, 2004 7:09 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: [xsl] RE: [Bu posta banka disindan gelmekte olup gerektiginde teyit alinmalidir.] - [xsl] find the sum over distinct nodes - Sender blacklisted I found that Dave Pawson's FAQ was also very helpful when I had to solve the flat-to-structured problem. The portion of the FAQ that deals with turning flat documents into structured documents is at http://www.dpawson.co.uk/xsl/sect2/flatfile.html My thanks to Jeni and Dave for creating these resources and to everyone on the list for all the input. Jay Bryant Bryant Communication Services "Michael Kay" <mike@xxxxxxxxxxxx> 11/18/2004 10:55 AM Please respond to xsl-list@xxxxxxxxxxxxxxxxxxxxxx To <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> cc Subject RE: [xsl] RE: [Bu posta banka disindan gelmekte olup gerektiginde teyit alinmalidir.] - [xsl] find the sum over distinct nodes - Sender blacklisted Last time Jarno showed you what to do, you did something different and then said it didn't work. Now you still say it doesn't work, but you're not telling us what you've done this time. Show a complete source document, a complete stylesheet, the output you are getting, and the output that you want. It's going to be difficult for you to use Jarno's code correctly unless you study it enough to understand it. Reading Jeni's XSLT grouping pages will help greatly: http://www.jenitennison.com/xslt/grouping Michael Kay http://www.saxonica.com/
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