Subject: [xsl] how to set the pattern to get the node From: que Li <queincanada@xxxxxxxx> Date: Mon, 29 Nov 2004 18:42:56 -0500 (EST) |
Hi: I can't figure out this problem for several days. I just wonder is it possible for me to filter node bu the select ? xml: <Lists> <List> <List_ID>11</List_ID> <Title>A1</Title> <Parent_ID>10</Parent_ID> </List> <List> <List_ID>10</List_ID> <Title>A</Title> <Parent_ID>1</Parent_ID> </List> <List> <List_ID>12</List_ID> <Title>A2</Title> <Parent_ID>10</Parent_ID> </List> <List> <List_ID>13</List_ID> <Title>C</Title> <Parent_ID>16</Parent_ID> </List> </Lists> How I can get the node which parent_ID =1 or parent_ID is not 1 but No other sibling node List_ID equal to current node parent_ID I try to use: <xsl:template match="List[Parent_ID=1 or not(../List[List_ID = current()/Parent_ID])] "> But don't work Thanks ______________________________________________________________________ Post your free ad now! http://personals.yahoo.ca
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