Subject: Re: [xsl] Understanding Identity Transformations From: David Carlisle <davidc@xxxxxxxxx> Date: Sun, 13 Feb 2005 18:30:23 GMT |
Tempore 14:47:08, die 02/13/2005 AD, hinc in xsl-list@xxxxxxxxxxxxxxxxxxxxxx scripsit David Carlisle <davidc@xxxxxxxxx>: > If A is a node set with two or more nodes that are not string-equal > then A != x is always true for any value of x. That's interesting... So you can use not(A!=B) to check if all nodes in two node-sets A and B are stingwise identical; Now isn't this a good use of '!=' ? not(A!=B) is true just if A!=B is false which is only the case if every node in A is equal to every node in B. If that's what you want to test for then the expression is put to good use, but it's rather rare to have a node set where all the nodes are string equal (unless it's something like @abc where you know there is at most one node in the set). David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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