Subject: [xsl] Finding the position of node in foreign node list From: "Jan Rademan" <jrademan@xxxxxxxxxxx> Date: Thu, 3 Mar 2005 22:18:31 +0200 |
Hi Here is a problem I'm playing around with: I have two variables containing two sets of nodes. $A contains 5 elements A,B,C,D,E of element type Service $B contains a subset of A$ e.g 2 elements B and D I am using them to create a table which looks like this A B C D E (Table header, which comes from $A) B D (First table row, which comes from $B) $B is reset though a for-each loop, which then loops to fill the table: A B C D E B D A C D E and so on. The for each which runs through the table, builds the table by running though each element in $A and checking to see if it exists in $B. If so, the value written. I need to determine the positional value of the element being written, as it occurs in the in the variable $B If I just use the postion function, I get the position value from the superset variable $A so I get output like this: A B C D E 2 4 1 3 4 5 The ouput I am looking for should rather list the position as it occurs in the subset variable $B: A B C D E 1 2 1 2 3 1 Any ideas how I can find out what the position of the current node is in a foreign node set? (As opposed to the position in the current node set) Thanks. Jan Rademan
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