Subject: Re: [xsl] Re: xsl-list Digest 22 Mar 2005 06:10:01 -0000 Issue 364 From: "Joe Fawcett" <joefawcett@xxxxxxxxxxx> Date: Tue, 22 Mar 2005 15:39:18 -0000 |
I'd normally suggets this link as this is a sort of grouping problem:Hi Friends, I'm having an xml as follows <webapps> <applications> <application> <name>Application1</name> <id>1</id> <users> <user> <name>Arjun</name> <accessrestrictions>some text</accessrestrictions> </user> <user> <name>user2</name> <accessrestrictions>some text</accessrestrictions> </user> <user> <name>user3</name> <accessrestrictions>some text</accessrestrictions> </user> <user> <name>user4</name> <accessrestrictions>some text</accessrestrictions> </user> </users> </application> <application> <name>Application2</name> <id>2</id> <users> <user> <name>arjun</name> <accessrestrictions>some text</accessrestrictions> </user> <user> <name>sruthi</name> <accessrestrictions>some text</accessrestrictions> </user> </users> </application> </applications> </webapps>
I'm trying to list the name,id and then all the users for the application using xsl <xsl:for-each select="webapps/applications/application"> <xsl:variable name="curid" select="id" /> <xsl:for-each select="webapps/applications/application/users/user"> <xsl:value-of select="$curid" /> <xsl:value-of select="name" /> <xsl:value-of select="accessrestrictions" /> </xsl:for-each> </xsl:for-each>
But the above code does not work. can anybody help me.
Thanks in advance, Kumar S
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