Subject: [xsl] replacement example , help From: henry human <henry_human@xxxxxxxx> Date: Tue, 29 Mar 2005 13:01:06 +0200 (CEST) |
hello, In this xsl styesheet i will replace aa with the string cc, what do i wrong ,that i dont get cc? thank you to have a look on this stylesheet: <?xml version="1.0"?> <?xml-stylesheet type="text/xsl" href="replace.xsl"?> <document> <part1> <name>uaabb</name> </part1> </document> ------------ <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html"/> <xsl:template name="part1"> <xsl:param name="name"/> <xsl:param name="aa"/> <xsl:param name="cc"/> <xsl:choose> <xsl:when test="contains($name,$aa)"> <xsl:value-of select="substring-before($name,$aa)"/> <xsl:value-of select="$cc"/> <xsl:call-template name="part1"> <xsl:with-param name="name" select="substring-after($name,$aa)"/> <xsl:with-param name="aa" select="$aa"/> <xsl:with-param name="cc" select="$cc"/> </xsl:call-template> </xsl:when> <xsl:otherwise> <xsl:value-of select="$name"/> </xsl:otherwise> </xsl:choose> </xsl:template> </xsl:stylesheet> ___________________________________________________________ Gesendet von Yahoo! Mail - Jetzt mit 250MB Speicher kostenlos - Hier anmelden: http://mail.yahoo.de
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