Re: [xsl] sort order elements

Subject: Re: [xsl] sort order elements
From: David Carlisle <davidc@xxxxxxxxx>
Date: Wed, 30 Mar 2005 17:47:34 +0100
  from the following xml database i am trying to output elements in reverse
  order :

well actually you seem to want to keep the element nodes in the same order
but swap round thir children

so something like

<xsl:template match="car">
<xsl:copy>
<xsl:for-each select="*">
<xsl:variable name="x" select="position()"/>
<xsl:copy>
 <xsl:copy-of select="../*[last()+1-$x]/*"/>
</xsl:copy>
</xsl:for-each>
</xsl:copy>
</xsl:template>

David

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