Subject: RE: [xsl] list of homogeneus elements semantically different... From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Fri, 1 Apr 2005 14:33:01 +0100 |
It's the same as the problem of arranging items in a two-column table, which is well covered in the FAQ. The key is that "position() mod 2" is zero for even-numbered elements. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: dalloro@xxxxxxxxx [mailto:dalloro@xxxxxxxxx] > Sent: 01 April 2005 13:57 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] list of homogeneus elements semantically different... > > Hi, > > How can I translate a structure like the following: > > <m t="6"> > <m t="0" e="2000"/> > <m t="0" e="141"/> > <m t="0" e="3000"/> > <m t="0" e="143"/> > <m t="0" e="6000"/> > <m t="0" e="142"/> > <m t="0" e="7000"/> > <m t="0" e="145"/> > <m t="0" e="11000"/> > <m t="0" e="185"/> > <m t="0" e="28000"/> > <m t="0" e="140"/> > </m> > > into a structure like this: > > <A a="2000" b="141" /> > <A a="3000" b="143" /> > <A a="6000" b="142" /> > <A a="7000" b="145" /> > <A a="11000" b="185" /> > <A a="28000" b="140" /> > > I don't know how to distinguish among the first and the second element > "m" in the list...Any ideas? > > Best regards. > > Livio
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