Subject: Re: [xsl] xsl templates match does not work From: David Carlisle <davidc@xxxxxxxxx> Date: Wed, 6 Apr 2005 17:28:31 +0100 |
> I am calling it as follows. I thought you might be:-) <xsl:template match="/"> so here the current node is the root node. and that is still the case here <xsl:call-template name="summaryTable"/> so you need to use any XPath's relative to that so header/row/total_due not just total_due Or perhaps simpler change <xsl:template name="summaryTable"> to <xsl:template match="row"> and change <xsl:call-template name="summaryTable"/> to <xsl:apply-templates select="header/row"/> so that the current node when your template is executed is the row node. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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