Re: [xsl] Trying to build a schema and add a namespace

Subject: Re: [xsl] Trying to build a schema and add a namespace
From: David Carlisle <davidc@xxxxxxxxx>
Date: Wed, 20 Apr 2005 01:17:27 +0100
Generating namespace nodes is a faq, I'm sure DaveP's faq pages will
have essentially the following, but...

If you are using xslt2 draft you can use the new <xsl:namespace
instruction added for just this reason.

If you are using the current XSLT1 rec then there are essentially two
ways to get a namespace node in to the result:

copy it from the source or generate an element or attribute in that
namespace and let the xslt system infer the namespace node.

You don't say what your input looks like

> My source file has a list of the target namespace and the files to
> import 

If the namespace information is actually stored in the input file as
namespaces then you are in good shape, you can just copy the namespace
nodes from the source tree using the namespace axis.

If you don't store the information as namespaces but just store the
namespace URI in element or attribute content then you have two choices:

suppose your source has
 <pfx>accord-doc</pfx>
 <ns>ACORD doc URL</ns>
and you want to generate
           xmlns:acord-doc="ACORD doc URL"

Then you can either go
<xsl:attribute name="{pfx}:foo" namespace="{ns}"/>
which will put 
accord-doc:foo=""  xmlns:acord-doc="ACORD doc URL"
into the result and you either live with the paccord-doc:foo attribute
or kill it with a post-process, or if you have a xx:node-set() extension
function you can do
<xsl:variable name="x">
<x>
<xsl:attribute name="{pfx}:foo" namespace="{ns}"/>
</x>
</xsl:variable>
<xsl:copy-of select="xx:node-set($x)/x/namespace::*[.=current()/ns]"/>
which will just copy the namespace node to the result tree.

David



you shouldn't ever need
           xmlns:xml="W3C url for XML namespace - need for xml:lang use"

should you XSLT won't generate this one, result trees always have this
namespace node but the serialisation never puts in the namespace
declaration, as it's always implictly declared anyway.


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